Finite Math Examples

10 P 2

${}_{10}P_{2}$

Step 1

Evaluate

10 P 2

${}_{10}P_{2}$ using the formula

n P r = \frac{n!}{(n - r)!}

${}_{n}P_{r} = \frac{n!}{(n - r)!}$ .

\frac{10!}{(10 - 2)!}

$\frac{10!}{(10 - 2)!}$

Step 2

Subtract

2

$2$ from

10

$10$ .

\frac{10!}{(8)!}

$\frac{10!}{(8)!}$

Step 3

Simplify

\frac{10!}{(8)!}

$\frac{10!}{(8)!}$ .

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Step 3.1

Rewrite

10!

$10!$ as

10 \cdot 9 \cdot 8!

$10 \cdot 9 \cdot 8!$ .

\frac{10 \cdot 9 \cdot 8!}{(8)!}

$\frac{10 \cdot 9 \cdot 8!}{(8)!}$

Step 3.2

Cancel the common factor of

8!

$8!$ .

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Step 3.2.1

Cancel the common factor.

$\frac{10 \cdot 9 \cdot 8!}{(8)!}$

Step 3.2.2

Divide

$10 \cdot 9$ by

$1$ .

$10 \cdot 9$

$10 \cdot 9$

Step 3.3

Multiply

$10$ by

$9$ .

$90$

$90$

${}_{10}P_{2}$

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$